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What Is The Radius Of A Circle Whose Equation Is X2 + Y2 + 8x – 6y + 21 = 0?

. X² + y² + 8x − 6y + 21 = 0. The given equation can be rewritten in the standard form as follows:

What is the radius of a circle whose equation is x2 + y2 + 8x 6y + 21
What is the radius of a circle whose equation is x2 + y2 + 8x 6y + 21 from brainly.com

Add 24 24 to both sides of the equation. Where (h, k) is the coordinates of the center of the circle and a is the radius. The equation of circle c is:

Each Such Circle Has An.


Hence for the given circle, the. X 2 + y 2. Video answer:in the given question.

(X −H)2 +(Y−K)2 = R2 ( X − H) 2 + ( Y − K) 2 = R 2.


Where (h, k) is the coordinates of the center of the circle and a is the radius. The equation can be written. There is an infinite number of circles whose diameter is on a radius of circle c.

The Equation Of The Circle Is Given As.


The given equation can be rewritten in the standard form as follows: X² + y² + 8x − 6y + 21 = 0. Hence, by collecting like terms and subsequent factorisation by completing the square method, it follows that;

Add 24 24 To Both Sides Of The Equation.


The standard form of the equation of the circle is. Video answer:we are going to do problem number 57. Where (h, k) is the coordinates of the center of the circle and a is the radius.

R Is The Radius Of The Circle.


The following equation is given to us and we are told. (h, k) is the center of the circle. The given equation can be rewritten in the standard form as follows:

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